A screen with a width of 125 inches and a throw ratio of 2.3:1 requires what distance of the projector from the screen?

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To determine the required distance of the projector from the screen based on the given width and throw ratio, you can apply the formula for throw distance:

[

\text{Throw Distance} = \text{Width} \times \text{Throw Ratio}

]

In this case, the width of the screen is 125 inches, and the throw ratio is 2.3:1. This means that for every 2.3 units of distance from the projector to the screen, one unit of width is needed.

Using the formula:

[

\text{Throw Distance} = 125 , \text{inches} \times 2.3

]

Calculating this gives:

[

\text{Throw Distance} = 287.5 , \text{inches}

]

This means the projector must be placed approximately 287.5 inches away from the screen to achieve the desired image size. This value aligns with the physical requirements of the system to ensure the projected image fills the screen properly without distortion or loss of quality.

The choice reflecting this calculation accurately points to the required distance, making it the correct answer.

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