For an Image Height of 48 inches using a 3 Percent Element Height on a 4K display, what is the Farthest Viewer distance?

To determine the farthest viewer distance for a 4K display with an image height of 48 inches and a 3 percent element height, you start by calculating the minimum viewing angle that corresponds to the specified element height as a percentage of the image height.

The element height in this case can be calculated as 3 percent of 48 inches. This amounts to 1.44 inches (0.03 x 48). For a 4K display, the recommended viewing distance is typically based on the screen resolution to ensure that the viewer can discern the detail without strain. The general guideline suggests that for every inch of screen height, the viewer should sit approximately 3 to 5 times that distance away, depending on the display resolution.

Using the 4K specification, which has a higher pixel density, sitting at 3 times the screen height is usually adequate for optimal viewing. Therefore, for a display height of 48 inches, the farthest recommended viewing distance would be 48 inches multiplied by 3, leading to a distance of 144 inches.

However, when contextualized within the available choices and after ensuring consistent presentation, it appears that the appropriate selection here would be an interpretation or simplification that translates this recommendation into the nearest