If 100% of energy is measured at a surface 1 meter from the source and is moved to 2 meters, what percentage of energy is measured at the new location?

To determine the percentage of energy measured at a distance of 2 meters from a source compared to the energy measured at 1 meter, it's essential to understand how the intensity of energy behaves as it radiates outward from a point source. The intensity of energy (or sound, light, etc.) decreases with the square of the distance from the source. This is described by the inverse square law, which states that intensity is inversely proportional to the square of the distance from the source.

At 1 meter from the source, let's assume 100% of the energy is measured. When moving to 2 meters, the distance has doubled. According to the inverse square law, the intensity at this new distance can be calculated as follows:

1. At 1 meter: Intensity = 100% (this is our reference point).

2. At 2 meters: Intensity = 100% / (2^2) = 100% / 4 = 25%.

This means that 25% of the original energy is measured at the surface 2 meters away from the source. As a result, the correct answer indicates that at 2 meters from the source, only 25% of the energy is present compared to what is