If a loudspeaker produces 70 dBSPL at 12.5 feet, what level will it produce at 25 feet?

To determine the sound pressure level (SPL) produced by a loudspeaker at a different distance, it’s important to understand the relationship between distance and sound intensity. Sound intensity decreases as the distance from the source increases, specifically following the inverse square law. This law states that the sound level decreases by approximately 6 dB for every doubling of the distance from the source.

In this scenario, the loudspeaker is producing a level of 70 dBSPL at 12.5 feet. When the distance is increased to 25 feet, which is a doubling of the original distance (12.5 feet to 25 feet), the SPL will drop by about 6 dB. Therefore, the calculation would be:

70 dBSPL - 6 dB = 64 dBSPL at 25 feet.

The correct answer reflects this calculation correctly, showing that the expected decrease in sound level due to the doubling of distance will bring the level down to around 64 dBSPL, not the higher values presented in other choices. It's crucial to understand the principles behind how sound level behaves with distance to accurately determine the correct resounding level at any given distance.