If a loudspeaker produces 90 dBSPL at 5 meters, what would be the measured level at 10 meters, assuming a standard drop?

To accurately assess how sound level decreases with distance, it's important to understand the inverse square law, which states that sound level decreases by 6 dB each time the distance from the source is doubled, provided that there are no significant issues with absorption or other variances in the environment.

In this scenario, the loudspeaker produces a sound level of 90 dBSPL at a distance of 5 meters. When the distance is increased to 10 meters, which is double the original distance, the expected decrease in sound level due to the inverse square law is 6 dB.

To calculate the new sound level at 10 meters:

• Start with the original sound level of 90 dBSPL.

• Subtract the 6 dB drop due to doubling the distance: 90 dBSPL - 6 dB = 84 dBSPL.

Thus, the sound level at 10 meters would be 84 dBSPL, indicating that this option correctly reflects the application of the inverse square law in sound level attenuation as distance from the source increases.